Wikipedia:WikiProject Council/Proposals/Mozilla
The new proposal has been made here: Wikipedia:WikiProject Council/Proposals/Mozilla (2nd nomination)
- The following discussion is an archived proposal of the WikiProject below. Please do not modify it. Subsequent comments should be made on the appropriate discussion page (such as the project's talk page (if created) or the WikiProject Council). No further edits should be made to this page.
The resulting WikiProject was not created
Contents
Description
editTo better document Mozilla, its projects (Firefox, Thunderbird, etc.), its goals, its community, etc., with a focus on better documenting how Mozilla applications work. —Waterfox (talk) 23:09, 9 August 2010 (UTC)[reply]
Support
editPlease specify whether or not you would join the project.
- Waterfox (talk) 23:09, 9 August 2010 (UTC)[reply]
- EWikistTalk 20:02, 13 August 2010 (UTC) I'll have to see the final result to decide if I want to join, but sounds like it could be a good project![reply]
Oppose
edit- Per Kirill, the scope simply isn't big enough to support a full project. A taskforce is a good idea, though. Matthewedwards : Chat 03:16, 27 August 2010 (UTC)[reply]
- Yes, a task force is enough. Maybe once the company widens it can be a full-blown WikiProject. -Vaarsivius (Talk to me.) 09:47, 26 October 2010 (UTC)[reply]
Discussion
edit- How similar would the scope of this project be to Wikipedia:WikiProject Software/Free Software? EWikistTalk 20:06, 13 August 2010 (UTC)[reply]
- This might be better off as a subgroup of WikiProject Software; I doubt that there are sufficient articles on Mozilla in particular to warrant setting up and maintaining an entirely separate WikiProject. Kirill [talk] [prof] 01:45, 18 August 2010 (UTC)[reply]
- The above discussion is preserved as an archive of the debate. Please do not modify it. Subsequent comments should be made on the appropriate discussion page (such as the project's talk page (if created) or at the WikiProject Council). No further edits should be made to this page.