From November 8 to December 8, 1910, a World Chess Championship match was played in Berlin between the champion Emanuel Lasker and the challenger David Janowski. It was the second world championship match played in 1910, following Lasker's title defense against Carl Schlechter earlier that year. Lasker successfully defended his title, with the score—Lasker winning 8 games, Janowski winning none, and 3 draws—being the most one-sided in World Chess Championship history.
|
Defending champion |
Challenger | |||||
 |
 | |||||
 Emanuel Lasker |
 David Janowski | |||||
| ||||||
|
Born 24 December 1868 41 years old |
Born 25 May 1868 42 years old | |||||
|
| ||||||
Background
editLasker and Janowski played two exhibition matches in 1909, the first drawn (+2 -2) and the second won convincingly by Lasker (+7 =2 -1). The longer 1909 match has sometimes been called a world championship match,[1] but research by Edward Winter indicates that the title was not at stake.[2]
Results
editThe first player to win eight games would be World Champion.
World Chess Championship Match Nov-Dec 1910 1 2 3 4 5 6 7 8 9 10 11 Wins Total 
Emanuel Lasker (Germany)
1 = = 1 1 = 1 1 1 1 1 8 9½ 
David Janowski (France)
0 = = 0 0 = 0 0 0 0 0 0 1½
Lasker retained the title in the most one-sided World Championship of all time.
Notes
edit- ^ For instance: "From Morphy to Fischer", Israel Horowitz, Batsford 1973, p. 64; "The Centenary Match - Kasparov-Karpov III", Raymond Keene and David Goodman, Batsford 1986
- ^ Chess Notes 5199, by Edward Winter
External links
edit- 1910 World Chess Championship at the Internet Archive record of Graeme Cree's Chess Pages