1976 Alan King Tennis Classic – Doubles

Fourth-seeded pair Arthur Ashe and Charlie Pasarell won the title, defeating top-seeds Bob Lutz and Stan Smith in the final.[1]

Doubles
1976 Alan King Tennis Classic
Final
ChampionsUnited States Arthur Ashe
United States Charlie Pasarell
Runners-upUnited States Bob Lutz
United States Stan Smith
Score6–4, 6–2
Events
Singles Doubles
← 1975 · Alan King Tennis Classic · 1977 →

Draw

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Draw

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First round Quarterfinals Semifinals Final
1   B Lutz
  S Smith
7 7  
    J Andrews
  C Richey
5 6   1   B Lutz
  S Smith
6 7  
    L Hoad
  J McManus
2 4       R Case
  G Masters
4 5  
    R Case
  G Masters
6 6   1   B Lutz
  S Smith
6 6  
    D Stockton
  R Tanner
4 5       B Carmichael
  K Rosewall
4 2  
    B Carmichael
  K Rosewall
6 7       B Carmichael
  K Rosewall
6 7  
    B Gottfried
  H Solomon
6 7       B Gottfried
  H Solomon
4 6  
3   A Emerson
  J Newcombe
4 5   1   B Lutz
  S Smith
4 2  
4   A Ashe
  C Pasarell
6 7 6 4   A Ashe
  C Pasarell
6 6  
    D Bohrnstedt
  T Koch
7 5 3 4   A Ashe
  C Pasarell
7 6  
    T Gorman
  S Stewart
3 7 3     V Amritraj
  A Panatta
6 3  
    V Amritraj
  A Panatta
6 6 6 4   A Ashe
  C Pasarell
6 3 7
    P Gonzales
  F Sedgman
1 6 3 2   J Connors
  E van Dillen
4 6 6
    B Hewitt
  R Moore
6 4 6     B Hewitt
  R Moore
6 2  
    B McKinley
  V Seixas
3 2   2   J Connors
  E van Dillen
7 6  
2   J Connors
  E van Dillen
6 6  

References

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General
  • "Doubles Draw". atpworldtour.com. ATP Tour, Inc. Retrieved 2016-05-01.
Specific
  1. ^ "Connors Merciless to Kind Rosewall". The Pittsburgh Press. 1976-05-17.