1978 WCT Tournament of Champions – Singles

Harold Solomon was the defending champion, but lost in semifinals to Vitas Gerulaitis.[1]

Singles
1978 WCT Tournament of Champions
Final
ChampionSweden Björn Borg
Runner-upUnited States Vitas Gerulaitis
Score6–5, 5–6, 6–4, 6–5
Details
Draw16
Seeds4
← 1977 · WCT Tournament of Champions · 1979 →

Second-seeded Björn Borg won the title by defeating third-seeded Vitas Gerulaitis 6–5, 5–6, 6–4, 6–5 in the final.[2]

Seeds

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  1.   Jimmy Connors (first round)
  2.   Björn Borg (champion)
  3.   Vitas Gerulaitis (final)
  4.   Eddie Dibbs (quarterfinals)

Draw

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First round Quarterfinals Semifinals Final
1   Jimmy Connors 3 0
  Jeff Borowiak 6 6   Jeff Borowiak 4 2
  Vijay Amritraj 4 4   Harold Solomon 6 6
  Harold Solomon 6 6   Harold Solomon 4 1
  Sandy Mayer 6 6 3   Vitas Gerulaitis 6 6
  Ilie Năstase 2 2   Sandy Mayer 4 6 3
  John Alexander 3 3 3   Vitas Gerulaitis 6 5 6
3   Vitas Gerulaitis 6 6 3   Vitas Gerulaitis 5 6 4 5
4   Eddie Dibbs 6 6 2   Björn Borg 6 5 6 6
  Ken Rosewall 3 4 4   Eddie Dibbs 3 2
  Cliff Drysdale 6 6   Cliff Drysdale 6 6
  Tim Gullikson 1 2   Cliff Drysdale 4 5
  Dick Stockton 6 4 5 2   Björn Borg 6 6
  Tony Roche 5 6 6   Tony Roche 4 2
  Rod Laver 4 2 2   Björn Borg 6 6
2   Björn Borg 6 6

References

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  1. ^ "Borg and Gerulaitis Advance to Final". The New York Times. Las Vegas. March 26, 1978. Retrieved October 27, 2018. Borg was pushed to the limit by Cliff Drysdale, an added starter, before winning his semifinal, 6‐4, 6‐5, with a 7‐5 tiebreaker. Gerulaitis defeated Harold Solomon, 6‐4, 6‐1.
  2. ^ "Borg vexes Vitas". Las Vegas: The Hutchinson News. United Press International. March 27, 1978. p. 7. Retrieved October 27, 2018.
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