2019 Lale Cup – Doubles

Ayla Aksu and Harriet Dart were the defending champions, but both players chose not to participate.

Doubles
2019 Lale Cup
Final
ChampionsCzech Republic Marie Bouzková
Netherlands Rosalie van der Hoek
Runners-upBelarus Ilona Kremen
Belarus Iryna Shymanovich
Score7–5, 6–7(2–7), [10–5]
Events
Singles Doubles
← 2018 · Lale Cup · 2020 →

Marie Bouzková and Rosalie van der Hoek won the title, defeating Ilona Kremen and Iryna Shymanovich in the final, 7–5, 6–7(2–7), [10–5].[1]

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   O Doroshina
  P Monova
    Ç Büyükakçay
  A Vrljić
w/o   Ç Büyükakçay
  A Vrljić
    G Poznikhirenko
  S Sharipova
7 4 [8]   M Bouzková
  R van der Hoek
w/o
    M Bouzková
  R van der Hoek
5 6 [10]   M Bouzková
  R van der Hoek
7 7
3   B Cengiz
  J Rompies
6 6 3   B Cengiz
  J Rompies
5 5
WC   Z Erman
  Z Sönmez
3 4 3   B Cengiz
  J Rompies
1 6 [11]
    İ Soylu
  B Štefková
6 6   İ Soylu
  B Štefková
6 4 [9]
WC   İ Öz
  M Sezer
3 3   M Bouzková
  R van der Hoek
7 62 [10]
    I Kremen
  I Shymanovich
6 6   I Kremen
  I Shymanovich
5 77 [5]
    Á Bukta
  V Juhászová
2 3   I Kremen
  I Shymanovich
4 6 [11]
    G Minnen
  P Özgen
7 6   G Minnen
  P Özgen
6 3 [9]
4   V Grammatikopoulou
  A Raina
5 4   I Kremen
  I Shymanovich
66 6 [11]
    A Gasanova
  J Terziyska
6 77 2   R Șerban
  I Shinikova
78 3 [9]
    F Al-Nabhani
  C Anıl
1 63   A Gasanova
  J Terziyska
6 62 [7]
WC   L Aiche
  BE Gümüşsoy
0 0 2   R Șerban
  I Shinikova
4 77 [10]
2   R Șerban
  I Shinikova
6 6

References

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  1. ^ "W60 Istanbul". www.itftennis.com.