Collatz Conjecture

     It has been noted that C(x) =(3x+1)/2**k is never divisible by 3.  This means that
     numbers divisible by 3 cannot form loops.  This appears to give a 33 percent speed up
     in checking for counter examples over just checking odds.  Is there any code that
     implements this efficiently?
     [1]

--Rlcsljo (talk) 23:44, 22 August 2018 (UTC)Reply

Information icon Welcome to Wikipedia. We appreciate your contributions, but in one of your recent edits to Collatz conjecture, it appears that you have added original research, which is against Wikipedia's policies. Original research refers to material—such as facts, allegations, ideas, and personal experiences—for which no reliable, published sources exist; it also encompasses combining published sources in a way to imply something that none of them explicitly say. Please be prepared to cite a reliable source for all of your contributions. Thank you. —David Eppstein (talk) 00:29, 15 September 2018 (UTC)Reply

May 2019

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Welcome to Wikipedia. Although everyone is welcome to contribute constructively to the encyclopedia, your addition of one or more external links to the page Tower of Power has been reverted.
Your edit here to Tower of Power was reverted by an automated bot that attempts to remove links which are discouraged per our external links guideline. The external link(s) you added or changed (https://www.facebook.com/events/653664081321202/) is/are on my list of links to remove and probably shouldn't be included in Wikipedia.
If you were trying to insert an external link that does comply with our policies and guidelines, then please accept my creator's apologies and feel free to undo the bot's revert. However, if the link does not comply with our policies and guidelines, but your edit included other, constructive, changes to the article, feel free to make those changes again without re-adding the link. Please read Wikipedia's external links guideline for more information, and consult my list of frequently-reverted sites. For more information about me, see my FAQ page. Thanks! --XLinkBot (talk) 23:48, 22 May 2019 (UTC)Reply

Your submission at Articles for creation: sandbox (June 24)

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Your recent article submission has been rejected. If you have further questions, you can ask at the Articles for creation help desk or use Wikipedia's real-time chat help. The reason left by Dan arndt was: undefined
Dan arndt (talk) 03:41, 24 June 2019 (UTC)Reply
 
Hello, Rlcsljo! Having an article declined at Articles for Creation can be disappointing. If you are wondering why your article submission was declined, please post a question at the Articles for creation help desk. If you have any other questions about your editing experience, we'd love to help you at the Teahouse, a friendly space on Wikipedia where experienced editors lend a hand to help new editors like yourself! See you there! Dan arndt (talk) 03:41, 24 June 2019 (UTC)Reply

User:Rlcsljo/sandbox

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Hello, Rlcsljo. It has been over six months since you last edited the Articles for Creation submission or draft page you started, User:Rlcsljo/sandbox.

In accordance with our policy that Wikipedia is not for the indefinite hosting of material deemed unsuitable for the encyclopedia mainspace, the draft has been deleted. If you plan on working on it further and you wish to retrieve it, you can request its undeletion by following the instructions at this link. An administrator will, in most cases, restore the submission so you can continue to work on it. — JJMC89(T·C) 03:31, 25 December 2019 (UTC)Reply

List of unusual deaths

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Hi Rlcsljo. Do you know what WP:RS means? Thanks. Martinevans123 (talk) 21:10, 4 February 2020 (UTC)Reply

February 2020

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  Hello, I'm Martinevans123. I wanted to let you know that one or more of your recent contributions to List of unusual deaths have been undone because they did not appear constructive. If you would like to experiment, please use the sandbox. If you have any questions, you can ask for assistance at the help desk. Thanks. Martinevans123 (talk) 21:31, 4 February 2020 (UTC)Reply